Life would be a lot easier if we had an even number of repeats, but IMO this is how the 5-2x guys should be assigned:
East
Atl: C2, E2, A1
Cen: D2, B1
West
Mid: B2, C1
Pac: A2, D1, E1
With this:
A has C&D and E twice
B has C&D
C has A&B&E
D has A&B&E
E has C&D and A twice
With 5 guys and 10 teams at least two teams MUST end up in the same division both times, two guys get 3 of the other 4, and the last guy gets 2 of the 4.
Now all you have to do is randomly assign each of the 5 guys a different letter, apply the above, and randomly put the other 14 guys in a division, and ur done.
4/30/2013 3:24 PM (edited)