This would accomplish the following:

(1) and most important, put jhsuk's two teams in separate conferences;

(2) Give each conference exactly three of the bottom six picks teams,

(3) Give each division exactly three of the multi-entry teams; and

(4) Give exactly two divisionss two of the bottom six while giving the other two exactly one.

East

Div 1: A1, F1, D2

Div 2: B1, C2, E2

West

Div 3: C1, E1, A2

Div 4: D1, B2, F2

Will explain the logic and the breakdown in a minute, suggest you re-assign the letters to the now six teams, then do your random draw for the remaining 12 of us.

The above gives you:

(1) None of the six have two teams in the same conference

(2) One division in each conference has two of the bottom six and the other has one, each conference gets exactly 3 of the 6 from the bottom group of 6.

(3) The other division in each conference has exactly one of the bottom six and two other teams owned by a guy from the group of six.

Teams and who they are paired with:

Team A: C,D,E,F

Team B: C,D,E,F

Team C: A,B, & E(2x)

Team D; A.B, & F(2x)

Team E: A,B, & C(2x)

Team F: A.B, & D(2x)

Note that the multi-team owner distribution and the 12 single teams are unique events and are not combined until the very end of the process.

Here is what I would do: place the 12-teams in Pods containing 3 teams each and assigned by WHERE they selected their first round pick. It is VERY IMPORTANT to note that you ignore the 12 multi-teams when assigning these slots, I'll provide a better explanation in a moment.

Here would be the Pods:

Eastern Conference

Pod #1: Pick 1, Pick 8, Pick 9

Pod #2: Pick 4, Pick 5, Pick 12

Western Conference

Pod #3: Pick 3, Pick 6, Pick 11

Pod #4: Pick 2, Pick 7, Pick 10

Will explain how this would impact us in just a minute in another post. For this to work you MUST assign letters A-E to the other six teams on a completely RANDOM basis, the MJ team should have the same chance at drawing letter A as it does B, C, D, E, or F.

1) jhsukow - IGNORE Part of 6-man

2) skypilot - IGNORE

3) badja - Pod #1(Pick 1)

4) thomcat - Pod #4(Pick 2)

5) husker75 - Pod #3 (Pick 3)

6) carbonjones - IGNORE

7) smokey57 - IGNORE

8) coachcroft - Pod #2 (Pick 4)

9) kdforester - Pod #2 (Pick 5)

10) steelers821 - Pod #3 (Pick 6)

11) shawbigred - Pod #4 (Pick 7)

12) alecmcafee - Pod #1 (Pick 8)

13) tanguma44 - IGNORE

14) natenoy - Pod #1 (Pick 9)

15) 98average - Pod #4 (Pick 10)

16) dh555 - Pod #3 (Pick 11)

17) seapilots - IGNORE

18) cmcafeeky - Pod #2 (Pick 12)

3) badja - Pod #1(Pick 1)

4) thomcat - Pod #4(Pick 2)

5) husker75 - Pod #3 (Pick 3)

6) carbonjones - IGNORE

7) smokey57 - IGNORE

8) coachcroft - Pod #2 (Pick 4)

9) kdforester - Pod #2 (Pick 5)

10) steelers821 - Pod #3 (Pick 6)

11) shawbigred - Pod #4 (Pick 7)

12) alecmcafee - Pod #1 (Pick 8)

13) tanguma44 - IGNORE

14) natenoy - Pod #1 (Pick 9)

15) 98average - Pod #4 (Pick 10)

16) dh555 - Pod #3 (Pick 11)

17) seapilots - IGNORE

18) cmcafeeky - Pod #2 (Pick 12)

EAST

Atlantic: badja, alecmcafee, natenoy, A1, F1, D2

Central: coachcroft, kdforester, cmcafeeky, B1, C2, E2

WEST

Midwest: husker75, steelers821, dh555, C1, E1, A2

Pacific: thomcat, shawbigred, 98average D1, B2, F2

I truly believe that using this suggested division assignment will give us the best chance at true parity in the league (the parity you have been talking about from the beginning smokey.) With the above we are VERY unlikely to end up with 6 really horrible teams in the same division and just as unlikely for one division to have 6 elite teams. With the above none of the divisions should become a cakewalk nor should they become a murders row.