natenoy
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Life would be a lot easier if we had an even number of repeats, but IMO this is how the 5-2x guys should be assigned:

East

Atl: C2, E2, A1

Cen: D2, B1

West

Mid: B2, C1

Pac: A2, D1, E1

With this:

A has C&D and E twice

B has C&D

C has A&B&E

D has A&B&E

E has C&D and A twice

With 5 guys and 10 teams at least two teams MUST end up in the same division both times, two guys get 3 of the other 4, and the last guy gets 2 of the 4.

Now all you have to do is randomly assign each of the 5 guys a different letter, apply the above, and randomly put the other 14 guys in a division, and ur done.