East

Atl: C2, E2, A1

Cen: D2, B1

West

Mid: B2, C1

Pac: A2, D1, E1

With this:

A has C&D and E twice

B has C&D

C has A&B&E

D has A&B&E

E has C&D and A twice

With 5 guys and 10 teams at least two teams MUST end up in the same division both times, two guys get 3 of the other 4, and the last guy gets 2 of the 4.

Now all you have to do is randomly assign each of the 5 guys a different letter, apply the above, and randomly put the other 14 guys in a division, and ur done.

alecmcafee kdforester steelers821 shawbigred natenoy cmcafeeky dh555 98average

skypilot 1 tanguma 1 smokey 1 jhsukow 1

carbonjones 1 smokey 2 seapilots 1 tanguma 2

jhsukow 2 seapilots 2 skypilot 2 carbonjones 2

Well now we know who our cellmates are for DDL #1

This may not be truly random due to to the 2 team owners, but it is surely without bias. Therefore the goal was achived.

Modified 5/2/13