OK, so here are the tiebreakers, from the HELP section -

A tiebreaker system is used if two or more teams tie for a playoff berth. Head-to-head record is used first, then division record, then run differential, then last season's record and finally a coin flip.

Great. Clear as mud for this situation.

If there are three teams tied for the best record in the League, how are the seeds determined? This deals specifically with H2H. Take this example:

Team A
6-4 vs Team B
6-4 vs Team C

Team B
4-6 vs Team A
9-1 vs Team C

Team C
4-6 vs Team A
1-9 vs Team C

In this scenario, Team C is the #3 seed. Of that, I'm pretty sure. But who would get the #1 seed? Team A or Team B?

It comes down to whether H2H is treated independently (i.e., Team A beat Team B H2H, so Team A is #1) or whether (when there are 3 teams with the same record) H2H is grouped together (in which case Team B went 13-7 against the two other teams with the same number of wins, while Team A went only 12-8, so Team B is #1).

I'll likely send in a ticket, but HBD responses have been slow for me lately and this may be resolved in the next day or so anyway, so I'm trying here in case someone can share first-hand experience (or a ticket that they have sent previously).

A #1 then B then C i think.
I seem to recall from somewhere it's best thinking of it as a league table. So A has 2W, B has 1W and C has 0W, so A, B, C.
So if A beat B, B beat C and C beat A, that is the scenario where you would proceed to the next tie breaker.
At least thats how i understood it but i may be wrong...

A beat them both, it goes to them. Using your same logic that C is the #3 seed "Of that, I'm pretty sure". the same logic applies on how you see it.

I'm pretty sure it's B.  It's total wins against all the other tied teams.

So team A was 12-8, team B was 13-7 and team C was 5-15.

Team B had the best record at 13-7.  Then A, then C.

Let us know how it turns out.

That's a good point.

My thought is:  Tiebreakers will first eliminate the "lowest" team.  That would be C since it doesn't win a tiebreaker against A, nor B.  The tiebreaker scenario for the final two teams is applied.  The winner of that scenario would be A.

Another good point.

This is all assuming that the 3 teams are from different divisions.  Is that correct?

Yet another good point.

Division ties would be resolved first.

So many good points. Happy New Year.

Posted by The__Kid on 12/31/2010 11:03:00 AM (view original):
This is all assuming that the 3 teams are from different divisions.  Is that correct?

They are, but thankfully it won't come to pass.

The three teams sit at 96 wins, 95 wins, and 94 wins now, with only one game left.

Posted by zbrent716 on 12/31/2010 1:10:00 PM (view original):

Posted by The__Kid on 12/31/2010 11:03:00 AM (view original):
This is all assuming that the 3 teams are from different divisions.  Is that correct?

They are, but thankfully it won't come to pass.

The three teams sit at 96 wins, 95 wins, and 94 wins now, with only one game left.

Damn!

Yeah really ;). I was hoping to find out what happened.

Edit: though currently in one of my worlds, 2 teams tied for a WC2 and another 1 game back with 1 to go. 3 divisions. So there's hope ;).

From CS - 

If three teams are tied it uses the overall record against each team that is tied. In this scenario Team B would receive the #1 seed.